6. sin150 Sin(90+60)=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2
7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2
cos(90+60)=−sin60∘=−8/2cos(180∘−30)=−cos30=−3/2
cos150
Video solution 1: 6. sin150 Sin(90+60)=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2
7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2
cos(90+60)=−sin60∘=−8/2cos(180∘−30)=−cos30=−3/2
cos150
Video solution 2: 6. sin150 Sin(90+60)=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2
7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2
cos(90+60)=−sin60∘=−8/2cos(180∘−30)=−cos30=−3/2
cos150
If sin 600° cos 30° + cos 120° sin 150° = k, then k = (a) 0 (b) 1 (c) −1 (d) None of these
Nilai Cos 15 Derajat Adalah, 110 Adalah 14 612 2 C GRATIS
Verify each of the following: (i) sin 60^∘cos 30^∘-cos 60^∘sin 30^∘=sin 30^∘ (ii) cos 60^∘cos 30^
⏩SOLVED:Evaluate the following: (i) sin60^∘ cos30^∘+sin30^∘ cos60^∘…
If sin 600° cos 30° + cos 120° sin 150° = k, then k = (a) 0 (b) 1 (c) −1 (d) None of these
SOLVED: -cos 30^∘=(√(3))/(2) -cos 60^∘=(1)/(2) -cos 90^∘=0 -cos 120^∘=(180^∘ -60^∘)=-cos 60^∘=-(1)/(2) -cos 180^∘=cos(180^∘-80^∘)=-cos 30^∘=(-√(3))/(2) -cos 180^∘=cos(180^∘-0^∘)=-cos 60^∘=-(1)/(2) -cos 210^∘=cos(180^∘+30^∘)=-30
Why sin30=cos60=1/2, sin60=cos30=square root 3 over 2, tan30=1/square root 3, tan60=square root 3 ?
Evaluate the followingi sin 60∘cos 30∘+sin 30∘cos 60∘ii 2 tan 2 45∘+cos 2 30∘ sin 2 60∘iii cos 45∘/ 30∘+cosec 30∘iv sin 30∘+tan 45∘ cosec 60∘/ 30∘+cos 60∘+ 45∘v 5 cos 2 60∘+4 2 30∘ tan 2 45∘/sin 2 30∘+cos 2 30∘
How to prove that sin 780 sin 480 + cos 120 sin 30=1/2 - Quora
Show that: cos 30+sin 60/ 1+sin 30+ cos 60 = cos 30 - Sarthaks eConnect